原题链接
题解
太巧妙了!!!
code
#include<bits/stdc++.h>
using namespace std;
int main()
{int n,m;cin>>n>>m; int r=0,b=0,y=0;for(int i=1;i<=n;i++){string s;cin>>s;for(int j=0;s[j];j++){if(s[j]=='1') r++;else if(s[j]=='2') b++;else if(s[j]=='3') y++;}}printf("%d %d %d\n",(2*r-y)/3,y-b,b-(r+y)/3);return 0;
}